Calculating renal clearance
A substance has a urine concentration of 30 mg/mL and a plasma concentration of 0.5 mg/mL, and urine flow is 2 mL/min. What is its clearance?
Answer D: explanation for every choice
A
This multiplies by plasma concentration and divides by urine flow: (U × P)/V.
B
This multiplies all three values.
C
This leaves out dividing by plasma concentration (U × V).
D
Correct. C = UV/P = (30)(2)/0.5 = 120 mL/min, close to a typical GFR.
TakeawayClearance = UV/P.
Equation usedRenal clearance
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