Work along an equipotential surface
How much work does the electric field do on a charge moved between two points on the same equipotential surface?
Answer C: explanation for every choice
A
Electrostatic work is path-independent.
B
qEd applies only when moving parallel to the field. Equipotential surfaces are perpendicular to it.
C
Correct. W = −qΔV, and ΔV = 0 between points at the same potential.
D
qE is a force, not work.
TakeawayEquipotential: ΔV = 0, so W = 0. The field is perpendicular to equipotential surfaces.
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Reviewed 2026-11-05 by a medical student. Spot an error? Report it with question ID cp126.