Calculating osmotic pressure
What is the osmotic pressure of 0.10 M NaCl at 300 K? (R = 0.0821 L·atm/mol·K; assume full dissociation)
Answer C: explanation for every choice
A
This uses 27 °C instead of 300 K.
B
This uses i = 1, ignoring dissociation.
C
Correct. Π = iMRT = (2)(0.10)(0.0821)(300) ≈ 4.93 atm.
D
This uses i = 3.
TakeawayΠ = iMRT, with T in kelvin.
Equation usedColligative properties
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