Wavelength of a string's third harmonic
A string 1.0 m long is fixed at both ends. What is the wavelength of its third harmonic?
Answer B: explanation for every choice
A
This uses λ = L/n instead of 2L/n.
B
Correct. For a string fixed at both ends, λ = 2L/n = 2(1.0)/3 ≈ 0.67 m.
C
This inverts the ratio, giving 3L/2.
D
2.0 m is the fundamental wavelength (n = 1).
TakeawayFixed at both ends: λₙ = 2L/n, fₙ = nf₁.
Equation usedStanding waves
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